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VIT Engineering VIT Engineering Solved Paper-2014

  • question_answer
    An eye can detect \[5\times {{10}^{4}}\]photons per square metre per sec of green light \[\left( \lambda =5000\overset{\circ }{\mathop{\text{A}}}\, \right)\]while the ear can detect \[{{10}^{-13}}W/{{m}^{2}}.\]. The factor by which the eye is more sensitive as a power detector then the ear is close to  

    A)            5                                            

    B) 10                   

    C) \[{{10}^{6}}\]                                    

    D) 15   

    Correct Answer: A

    Solution :

    \[{{K}_{C}}=\frac{{{k}_{f}}}{{{k}_{b}}}=\frac{1.1\times {{10}^{-2}}}{1.5\times {{10}^{-3}}}=7.33\]                     \[=\frac{normality}{Acidity}=\frac{0.1}{1}=0.1\] So, the minimum intensity to which the eye can respond.      \[{{M}_{1}}{{V}_{1}}={{M}_{2}}{{V}_{2}}\]      \[0.1\times 19.85={{M}_{2}}\times 20\]                \[{{M}_{2}}=0.09925\approx 0.099\] Now, lesser the intensity required by a detector for detection more sensitive it will be                    \[\Delta ABC\]


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