A) \[\frac{5}{40}A\]
B) \[\frac{5}{50}A\]
C) \[\frac{5}{10}A\]
D) \[\frac{5}{20}A\]
Correct Answer: B
Solution :
The diode in lower branch is forward and diode in upper branch is reversed biased, so \[=50\Omega \]
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