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VIT Engineering VIT Engineering Solved Paper-2014

  • question_answer
    An electron moves at right angle to a magnetic field of\[5\times {{10}^{-2}}\] T with a speed of \[6\times {{10}^{7}}\]m/s. If the specific charge of the electron is \[1.7\times {{10}^{11}}C/kg.\]The radius of the circular path will be

    A) 2.9 cm                  

    B) 3.9 cm

    C) 2.35 cm  

    D) 2 cm

    Correct Answer: C

    Solution :

       The formula for radius of circular path is           \[\Omega \]           \[\Omega \]            \[\Omega \]           \[l=\frac{15}{200}=7.5\times {{10}^{-2}}A\]                


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