A) -372 kcal
B) 162 kcal
C) -240 kcal
D) 183.5 kcal
Correct Answer: A
Solution :
Given (i) \[=\frac{1\times {{\left( 2 \right)}^{2}}}{{{\left( 400 \right)}^{2}}}\] (ii) \[=25\mu F\] (iii) \[\overline{B}.C=Y'\] Eqs. 2 (ii) + 3 (iii) ? (i) \[A+\left( \overline{B}.\overline{C} \right)=Y''\] \[\overline{A+\overline{B}.C}=Y\] = - 372 kcalYou need to login to perform this action.
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