VIT Engineering VIT Engineering Solved Paper-2014

  • question_answer
    circuit has a self-inductance of 1 H and carries a current of 2A. To prevent sparking, when the circuit is switched off, a capacitor which can withstand 400 V is used. The least capacitance of capacitor connected across the switch must be equal to

    A) 50 \[\mu F\]                      

    B) 25 \[\mu F\]

    C) 100\[\mu F\]                     

    D) 12.5 \[\mu F\]

    Correct Answer: B

    Solution :

    Energy stored in capacitor is equal to energy stored in inductance                    \[E=\Delta m{{c}^{2}}\]                          \[=0.5\times {{10}^{-3}}\times {{\left( 3\times {{10}^{8}} \right)}^{2}}\]                        \[=4.5\times {{10}^{13}}\]                        \[E=\frac{4.5\times {{10}^{13}}}{3.6\times {{10}^{6}}}\]


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