VIT Engineering VIT Engineering Solved Paper-2014

  • question_answer
    According to Bohr's theory, the angular momentum for an electron of 3rd orbit is

    A) 3 h               

    B) 1.5 h

    C)  9 h               

    D) \[2\frac{h}{\pi }\]

    Correct Answer: A

    Solution :

    Angular momentum, \[i={{n}_{e}}{{q}_{e}}+{{n}_{p}}{{q}_{p}}\]                    \[=3.13\times {{10}^{15}}\times 1.6\times {{10}^{-17}}\]


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