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VIT Engineering VIT Engineering Solved Paper-2014

  • question_answer
    \[Ph-C\equiv C-C{{H}_{3}}\xrightarrow{H{{g}^{2+}}/{{H}^{+}}}A,\]

    A)                                            

    B)

    C)                                                                               

    D)

    Correct Answer: A

    Solution :

    \[{{i}_{250}}=\frac{20-15}{250}=\frac{5}{250}\]                                          \[=\frac{20}{1000}=20mA\] \[{{i}_{Zener}}=20-15\]                                                         \[\frac{N}{{{N}_{0}}}={{\left( \frac{1}{2} \right)}^{n}}={{\left( \frac{1}{2} \right)}^{t/7}}\]


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