A) \[F{{e}^{2+}}\]
B) \[C{{u}^{+}}\]
C) Zn
D) \[N{{i}^{3+}}\]
Correct Answer: A
Solution :
\[\log 1-\log e=\frac{5}{7}\log \frac{1}{2}\] \[-1=\frac{5}{7}\left( -\log 2 \right)\] \[T=5{{\log }_{e}}2\] \[\left( \frac{1}{2} \right)={{\left( \frac{1}{2} \right)}^{t'/5{{\log }_{e}}2}}\]
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