A) 10
B) 100 \[{{T}_{b}}\]
C) \[\Delta {{T}_{b}},\]
D) \[\frac{\Delta {{T}_{b}}}{10}\]
Correct Answer: C
Solution :
We know that, \[=\frac{5R}{36}\] \[\lambda =\frac{36}{5R}\] \[e{{v}_{0}}+\phi =\frac{hc}{\lambda }\] \[ev{{'}_{0}}+{{\phi }_{0}}^{'}=\frac{hc}{\lambda '}\]
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