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VIT Engineering VIT Engineering Solved Paper-2014

  • question_answer
    \[MnO_{4}^{-}+8{{H}^{+}}+5{{e}^{-}}\to M{{n}^{2+}}+4{{H}_{2}}O;\]                                                \[{{E}^{\circ }}=1.51V\] \[Mn{{O}_{2}}+4{{H}^{+}}+2{{e}^{-}}\to M{{n}^{2+}}+2{{H}_{2}}O'\]                         \[{{E}^{\circ }}=1.23V{{E}^{\circ }}_{MnO_{4}^{-}|Mn{{O}_{2}}}is\]

    A)  1.70 V                  

    B)  0.91 V

    C)  1.37 V                  

    D) 0.548 V

    Correct Answer: D

    Solution :

     For the reaction, \[i=\frac{E}{R+r}\]                    \[0.5=\frac{E}{11+r}\] \[E=5.5+0.5r\]               \[0.9=\frac{E}{5+r}\]


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