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VIT Engineering VIT Engineering Solved Paper-2014

  • question_answer
    19.85 mL of 0.1 N NaOH reacts with 20 mL of HCI solution for complete neutralisation. The molarity of HCI solution is

    A) 9.9                                         

    B) 0.99

    C)  0.099                   

    D) 0.0099

    Correct Answer: C

    Solution :

    Molarity of base \[{{E}_{1}}={{V}_{1}}{{l}_{1}}{{t}_{1}}=15\times 10\times 8\]                 \[{{E}_{2}}={{V}_{2}}{{l}_{2}}{{t}_{2}}\]  \[=14\times 5\times 15\] \[\eta =\frac{{{E}_{2}}}{{{E}_{1}}}\times 100\]


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