A) 9.9
B) 0.99
C) 0.099
D) 0.0099
Correct Answer: C
Solution :
Molarity of base \[{{E}_{1}}={{V}_{1}}{{l}_{1}}{{t}_{1}}=15\times 10\times 8\] \[{{E}_{2}}={{V}_{2}}{{l}_{2}}{{t}_{2}}\] \[=14\times 5\times 15\] \[\eta =\frac{{{E}_{2}}}{{{E}_{1}}}\times 100\]You need to login to perform this action.
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