A) A
B) |A|
C) A|. l
D) None of these
Correct Answer: C
Solution :
Given, \[=2.35\times {{10}^{-2}}m\] |A| = 21 ? 20 = 1 \[r=2.35m\] \[L=\frac{{{\mu }_{r}}.{{\mu }_{0}}{{N}^{2}}A}{l}\] \[=\frac{600\times 4\pi \times {{10}^{-7}}\times {{\left( 2000 \right)}^{2}}\times \left( 1.5 \right)\times {{10}^{-4}}}{0.3}\]You need to login to perform this action.
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