A) 3x ? 4
B) 4x ? 3
C) 4x + 3
D) None of these
Correct Answer: B
Solution :
\[\text{i }\!\!\alpha\!\!\text{ l}\] \[l\alpha \frac{1}{{{d}^{2}}}\] \[i\alpha \frac{1}{{{d}^{2}}}\] \[q={{q}_{0}}\left( 1-{{e}^{\frac{-t}{CR}}} \right)\] On equating real and imaginary parts, we get \[V={{V}_{0}}\left( 1-{{e}^{-\frac{t}{CR}}} \right)\] and \[i=\frac{E}{R+r}\] \[0.5=\frac{E}{11+r}\] \[E=5.5+0.5r\] \[0.9=\frac{E}{5+r}\] \[E=4.5+0.9r\] = 4x - 3
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