A) 0
B) \[\frac{1}{4}\]
C) \[\frac{1}{2}\]
D) \[\frac{1}{4}\]
Correct Answer: B
Solution :
Let \[=\frac{100000}{99}\approx 1010\] \[\Rightarrow \] \[{{\text{C}}_{\text{6}}}{{\text{H}}_{\text{6}}}\left( \text{g} \right)\text{=}{{\text{p}}_{\text{1}}}\] \[{{H}_{2}}\left( g \right)={{p}_{2}}mm\] \[\therefore \] Which shows that f?(x) is positive for \[{{p}_{1}}+{{p}_{2}}=60mm\] and f?(x) is negative for \[{{C}_{6}}{{H}_{6}}\left( g \right)=0\] Hence, f(x) attains maximum at \[{{H}_{2}}\left( g \right)={{p}_{2}}-3{{p}_{1}}\]You need to login to perform this action.
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