A) 4
B) 1
C) 3
D) 2
Correct Answer: D
Solution :
Given, \[|z|=\frac{1}{4}\] Let \[z'=-1+8z\] \[\Rightarrow \] \[z=\frac{z'+1}{8}\] \[\Rightarrow \] \[|z|=\frac{|z'+1|}{8}\] \[\Rightarrow \] \[\frac{1}{4}=\frac{|z'+1|}{8}\] \[\Rightarrow \] |z? + 1| = 2 Hence, z? lies on a circle with centre (-1, 0) and radius 2.You need to login to perform this action.
You will be redirected in
3 sec