A) \[-131.2kJmo{{l}^{-1}}\]
B) \[+131.2kJmo{{l}^{-1}}\]
C) \[\text{-262}\text{.4kJmo}{{\text{l}}^{\text{-1}}}\]
D) \[\text{+262}\text{.4kJmo}{{\text{l}}^{\text{-1}}}\]
Correct Answer: A
Solution :
\[=\frac{{{10}^{-3}}\times 5\times {{10}^{3}}}{15\times {{10}^{-6}}\times 330}\]\[=\frac{100000}{99}\approx 1010\] \[\Rightarrow \] or \[{{\text{C}}_{\text{6}}}{{\text{H}}_{\text{6}}}\left( \text{g} \right)\text{=}{{\text{p}}_{\text{1}}}\] \[{{H}_{2}}\left( g \right)={{p}_{2}}mm\] or, \[\therefore \] or, \[{{p}_{1}}+{{p}_{2}}=60mm\]You need to login to perform this action.
You will be redirected in
3 sec