A) \[\frac{9\pi }{4}+\frac{1}{2}\]
B) \[\frac{9\pi }{4}-\frac{1}{2}\]
C) \[9\left( \frac{\pi }{4}-\frac{1}{2} \right)\]
D) \[9\left( \frac{\pi }{4}+\frac{1}{2} \right)\]
Correct Answer: C
Solution :
Area of required region \[x\pm y=0\] Area of circle ? Area of \[\sqrt{2}\] \[=2\times \left( 8 \right)=16\] \[{{x}^{2}}-{{y}^{2}}={{8}^{2}}\]You need to login to perform this action.
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