A) \[\frac{2q}{4\pi {{\varepsilon }_{0}}{{r}^{2}}}\]
B) \[\frac{q}{4\pi {{\varepsilon }_{0}}{{r}^{2}}}\]
C) \[\frac{\sqrt{3}q}{4\pi {{\varepsilon }_{0}}{{r}^{2}}}\]
D) \[\frac{\sqrt{2}q}{4\pi {{\varepsilon }_{0}}.{{r}^{2}}}\]
Correct Answer: C
Solution :
The magnitude of intensity of electric field at point C due to charge at A and B is \[56u=\frac{56}{14}Natom=4Natom\] So, the net intensity at point C is \[\begin{align} & CaC{{O}_{3}}\xrightarrow{Heat}CaO+C{{O}_{2}}\uparrow \\ & \text{XColourless} \\ & \text{gas} \\ \end{align}\] \[\begin{align} & CaO+{{H}_{2}}O\to Ca{{\left( OH \right)}_{2}} \\ & \text{ResidueY} \\ \end{align}\] \[\begin{align} & Ca{{\left( OH \right)}_{20}}+2C{{O}_{2}}\to Ca{{\left( HC{{O}_{3}} \right)}_{2}} \\ & \text{YExcessZ} \\ \end{align}\] \[\begin{align} & Ca{{\left( HC{{O}_{3}} \right)}_{2}}\xrightarrow{Heat}CaC{{O}_{3}}+C{{O}_{2}}\uparrow +{{H}_{2}}O \\ & ZX \\ \end{align}\]You need to login to perform this action.
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