A) \[\text{N}{{\text{H}}_{\text{4}}}\text{Cl}\]
B) \[\text{N}{{\text{H}}_{\text{4}}}\text{C}{{\text{O}}_{\text{3}}}\]
C) \[\text{N}{{\text{H}}_{\text{4}}}\text{N}{{\text{O}}_{2}}\]
D) \[FeS{{O}_{4}}\]
Correct Answer: A
Solution :
\[{{\left( {{X}_{L}}-{{X}_{C}} \right)}^{2}}=0\] \[\Rightarrow \] \[{{X}_{L}}={{X}_{C}}\] \[\Rightarrow \] \[\omega L=\frac{1}{\omega C}\] \[\therefore \]You need to login to perform this action.
You will be redirected in
3 sec