A) \[{{\sin }^{-1}}\left( \frac{9}{8} \right)\]
B) \[{{45}^{0}}\]
C) \[{{60}^{0}}\]
D) \[{{\sin }^{-1}}\left( \frac{8}{9} \right)\]
Correct Answer: D
Solution :
We know that for total internal reflection, the incident angle must be greater than or equal to the critical angle for which the refracted angle is \[\text{9}{{\text{0}}^{\text{o}}}\] Here, \[\frac{{{\mu }_{2}}}{{{\mu }_{1}}}=\frac{\sin i}{\sin {{90}^{o}}}\] \[\frac{4/3}{3/2}=\sin i\]or \[i={{\sin }^{-1}}\left( \frac{8}{9} \right)\]You need to login to perform this action.
You will be redirected in
3 sec