A) 4-bromo 3- chloro pent-1-ene
B) 2-bromo 3-chloro pentene
C) 4-bromo 2-chloro butene-1
D) 4-methyl 4-bromo 3-chloro butene
Correct Answer: A
Solution :
\[{{H}_{3}}{{C}^{5}}-\underset{H}{\overset{Br}{\mathop{\underset{|}{\overset{|}{\mathop{{{C}^{4}}-}}}\,}}}\,\underset{H}{\overset{Cl}{\mathop{\underset{|}{\overset{|}{\mathop{{{C}^{3}}}}}\,}}}\,-\underset{H}{\mathop{\underset{|}{\mathop{{{C}^{2}}}}\,}}\,={{C}^{1}}{{H}_{2}}\] Its IUPAC name is 4-bromo 3-chloro- pent-1-eneYou need to login to perform this action.
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