A) \[+\,2.34\,V\]
B) \[+1.56\,V\]
C) \[-1.56\,V\]
D) \[-2.34\,V\]
Correct Answer: B
Solution :
In the cell, Zn will act as anode and Ag will act as cathode. Hence, \[E_{cell}^{o}=E_{cathode}^{o}-E_{anode}^{o}\] \[=(0.80)-(0.76)\] \[=+1.56\,V\]You need to login to perform this action.
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