A) 36
B) 34
C) 32
D) 30
Correct Answer: A
Solution :
In \[Ni{{(CO)}_{4}}\][CO is a neutral ligand] E. A.N. of Ni = Atomic weight \[-\text{oxidation}\,\text{state}+2\times \text{ligands}\] \[=28-0+2\times 4=36\]You need to login to perform this action.
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