A) \[\text{2}\,{{\text{m}}^{3}}\]
B) \[8\,{{\text{m}}^{3}}\]
C) \[12\,{{m}^{3}}\]
D) \[\text{10}\,{{\text{m}}^{\text{3}}}\]
Correct Answer: C
Solution :
According to Charles law, \[\frac{{{V}_{1}}}{{{T}_{1}}}=\frac{{{V}_{2}}}{{{T}_{2}}}\](at constant pressure) \[\frac{4}{300}=\frac{{{V}_{2}}}{900}\] or \[{{V}_{2}}=\frac{4\times 900}{300}=12\,{{\text{m}}^{\text{3}}}\]You need to login to perform this action.
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