A) \[{{H}_{2}}\]
B) \[{{F}_{2}}\]
C) \[{{O}_{2}}\]
D) \[C{{l}_{2}}\]
Correct Answer: A
Solution :
Using the relation, we have \[{{\upsilon }_{rms}}=\frac{\sqrt{3RT}}{m}\] where, R = gas constant \[=8.31\,J/mole-K\] \[\therefore \] \[{{(1930)}^{2}}=\frac{3\times 8.31\times 300}{m}\] \[\therefore \] \[m=2\times {{10}^{-3}}kg=2g\] Hence, the gas having 2 g molecular weight is hydrogen.You need to login to perform this action.
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