A) 3\[\Omega \]
B) 4\[\Omega \]
C) 4.5 \[\Omega \]
D) 5\[\Omega \]
Correct Answer: B
Solution :
The circuit given in the question can be modified as This is a balanced Wheatstone bridge Equivalent resistance in upper arm is \[{{R}_{U}}=5+3=8\,\Omega \] Equivalent resistance in lower arm is \[{{R}_{L}}=5+3=8\,\Omega \] Therefore, equivalent resistance of \[{{\text{R}}_{\text{U}}}\]and \[{{\text{R}}_{\text{L}}}\] is \[R=\frac{{{R}_{U}}+{{R}_{L}}}{{{R}_{U}}+{{R}_{L}}}\] \[=\frac{8\times 8}{8+8}=4\,\Omega \]You need to login to perform this action.
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