A) 2.5 amp
B) 3.5 amp
C) 1.5 amp
D) 0.5 amp
Correct Answer: D
Solution :
The force between wires carrying equal current in same direction is given by \[F=\frac{{{\mu }_{0}}}{4\pi }\times \frac{2{{i}^{2}}.l}{r}\] \[30\times {{10}^{-7}}={{10}^{-7}}\times \frac{2\times {{i}^{2}}\times 9}{0.15}\] \[=120\times {{10}^{-7}}\times {{i}^{2}}\] \[{{i}^{2}}=\frac{30\times {{10}^{-7}}}{120\times {{10}^{-7}}}=0.25\text{amp}\] \[i=0.5\,amp\]
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