2. Solved Papers
  3. VMMC

VMMC VMMC Medical Solved Paper-2004

  • question_answer
    The force on a rocket moving with a velocity of 300 m/s is 210 N. Then the rate of combustion of the fuel will be

    A) 3.5 kg/sec                           

    B) 2.1 kg/sec           

    C)        1.4 kg/sec           

    D)        0.7 kg/sec

    Correct Answer: D

    Solution :

    Velocity of rocket \[u=300\text{ }m/s,\] Force F = 210 N The relation of force is given by \[F=u\left( \frac{dm}{dt} \right)\]                 or            \[\frac{dm}{dt}=\frac{F}{u}=\frac{210}{300}=0.7\,\text{kg/sec}\]


You need to login to perform this action.
You will be redirected in 3 sec spinner