A) 2.7g
B) 2.7mg
C) 0.27g
D) 0.54g
Correct Answer: C
Solution :
Given : current = 241.25 coulomb We know that 1 coulomb of electricity will deposit \[1.118\times {{10}^{-3}}\,g\] of silver. \[\therefore \] 241.25 coulomb electricity will deposit \[=(1.118\times {{10}^{-3}})\times 241.25\] = 0.27 g of silver.You need to login to perform this action.
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