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VMMC VMMC Medical Solved Paper-2004

  • question_answer
    The resistors of resistances 2\[\Omega \], 4\[\Omega \] 5\[\Omega \] are connected in parallel. The total resistance of the combination will be:

    A) \[\frac{20}{19}\Omega \]                                            

    B) \[\frac{19}{20}\Omega \]                            

    C) \[\frac{10}{20}\Omega \]                            

    D)        \[\frac{29}{10}\Omega \]

    Correct Answer: A

    Solution :

    The resistances \[2\Omega ,4\Omega \] and \[5\Omega \] Are connected in parallel combination. Therefore, resultant resistance is given by \[\frac{1}{R}=\frac{1}{R}+\frac{1}{4}+\frac{1}{5}=\frac{19}{20}\]                 or            \[R=\frac{20}{19}\Omega \]


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