A) adding \[\text{Mn}{{\text{O}}_{\text{2}}}\]to dil \[{{\text{H}}_{\text{2}}}\text{S}{{\text{O}}_{\text{4}}}\]
B) by passing \[\text{C}{{\text{O}}_{2}}\]into \[\text{Ba}{{\text{O}}_{\text{2}}}\]
C) by adding \[\text{N}{{\text{a}}_{\text{2}}}{{\text{O}}_{\text{2}}}\]to cold water
D) by adding \[\text{Pb}{{\text{O}}_{\text{2}}}\]into \[\text{KMn}{{\text{O}}_{\text{4}}}\]
Correct Answer: B
Solution :
We know that \[Ba{{O}_{2}}+C{{O}_{2}}+{{H}_{2}}O\xrightarrow{{}}BaC{{O}_{3}}+{{H}_{2}}{{O}_{2}}\] Thus in this reaction hydrogen peroxide \[({{H}_{2}}{{O}_{2}})\] is prepared.
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