A) Phenol
B) Aniline
C) Benzene
D) Nitro benzene
Correct Answer: B
Solution :
We know that \[\underset{\text{Aniline}}{\mathop{{{C}_{6}}{{H}_{5}}N{{H}_{2}}}}\,+\underset{\text{chloroform}}{\mathop{CHC{{l}_{3}}}}\,+3KOH\,\xrightarrow{{}}\] \[\underset{\text{phyenyl}\,\,\text{isocyanide}}{\mathop{{{C}_{6}}{{H}_{5}}NC+3KCl}}\,+3{{H}_{2}}O\] Thus in this reaction phenyl isocyanide is produced. This is called carbylamine reaction.
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