A) \[\text{AgCl}\]
B) \[\text{AgBr}\]
C) \[\text{Agl}\]
D) none of these
Correct Answer: A
Solution :
We know that in ammonia the order of solubility is \[\text{AgCl AgBr Agl}\text{.}\] Therefore, \[\text{AgCl}\] is more soluble in ammonia.
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