A) 100
B) 10.1
C) 10
D) 1.001
Correct Answer: A
Solution :
\[\omega =0.15\,g,\,W=15\,g,\] \[\Delta \,{{T}_{b}}=0.216\,{{\,}^{o}}C\] \[{{K}_{b}}=2.16{{\,}^{o}}C\] \[\therefore \] \[M=\frac{{{K}_{b}}\times \omega \times 1000}{\Delta {{\Tau }_{b}}\times W}\] \[=\frac{2.16\times 0.15\times 1000}{0.216\times 15}=100\]You need to login to perform this action.
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