VMMC VMMC Medical Solved Paper-2004

  • question_answer
    Equivalant weight of a bivalent metal is 37.2. The molecular weight of its chloride is

    A)  412.2                   

    B)         216                       

    C)  145.4                   

    D)         108.2

    Correct Answer: C

    Solution :

    Equivalent weight of bivalent metal = 36.2 \[\therefore \]  Atomic weight of metal \[=37.2\times 2=74.4\] \[\therefore \] Formula of chloride \[\text{= MC}{{\text{l}}_{\text{2}}}\] Hence, molecular weight of chloride \[\text{(MC}{{\text{l}}_{2}}\text{)}\,\text{=}\,\text{74}\text{.4}\,\text{+}\,\text{2}\times \text{35}\text{.5}\] \[=145.4\]


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