A) \[3.2\times {{10}^{-21}}J\]
B) \[3.2\times {{10}^{-19}}J\]
C) \[3.2\times {{10}^{-15}}J\]
D) \[3.2\times {{10}^{-17}}J\]
Correct Answer: B
Solution :
Using the relation \[KE=hv-{{\omega }_{0}}\] \[KE=6.2-4.2\,=2\,eV\] \[=2\times 1.6\times {{10}^{-19}}=3.2\times {{10}^{-19}}\,J\]You need to login to perform this action.
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