A) 0.10 m
B) 0.06 m
C) 0.20 m
D) 0.25 m
Correct Answer: A
Solution :
From the relation \[\frac{m{{\upsilon }^{2}}}{r}=Be\upsilon \] Here: \[\frac{e}{m}=5\times {{10}^{7}}\,C/kg\] \[\upsilon =2\times {{10}^{5}}m/s\] \[B=4\times {{10}^{-2}}\,\text{tesla}\] \[r=\frac{m\upsilon }{Be}\] ?(i) Now in equation (i), we put the given values, \[r=\frac{\upsilon }{\frac{e}{m}B}=\frac{2\times {{10}^{5}}}{5\times {{10}^{7}}\times 4\times {{10}^{-2}}}=0.1\,m\]
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