A) 100 cc
B) 400 cc
C) 104 cc
D) 2.5 cc
Correct Answer: D
Solution :
Applying the ideal gas law \[\frac{{{P}_{1}}{{V}_{1}}}{{{T}_{1}}}=\frac{{{P}_{2}}{{V}_{2}}}{{{T}_{2}}}\] ?(i) Here: \[{{T}_{1}}={{T}_{2}}\](given) and \[{{P}_{1}}=1\,\text{atm,}\,{{\text{V}}_{1}}=10\,cc,\,{{P}_{2}}=4\,\text{atm}\] Now from equation (i), \[{{P}_{1}}{{V}_{1}}={{P}_{2}}{{V}_{2}}\] \[10\times 1=4\times {{V}_{2}}\] \[{{V}_{2}}=2.5\,cc\]
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