A) \[\frac{3}{4}\]m/s
B) \[\frac{1}{3}\]m/s
C) \[\frac{3}{2}\]m/s
D) \[\frac{2}{3}\]m/s
Correct Answer: D
Solution :
Using law of conservation of momentum \[{{m}_{1}}{{u}_{1}}+{{m}_{2}}{{u}_{2}}=({{m}_{1}}+{{m}_{2}})\upsilon \] Here: \[{{m}_{1}}=10\,kg,\,\,{{m}_{2}}=20\,kg,\,{{u}_{1}}=2\,m/s,\] \[u=0\] So, \[10\times 2+0=(10+20)\upsilon \] \[\upsilon =\frac{20}{30}=\frac{2}{3}\,m/s\]
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