A) \[\frac{g}{3}\]
B) \[\frac{2}{3}g\]
C) \[\frac{3}{2}g\]
D) \[\frac{g}{2}\]
Correct Answer: A
Solution :
Let T is the tension in the string then net downward force \[=mg-T\] If a is downward acceleration then according to Newtons IInd law \[mg-T=ma\] Given: \[{{T}_{\min }}=\frac{2}{3}mg,\]then \[a={{a}_{\min }}\] So, \[mg-\frac{2}{3}mg=m{{a}_{\min }}\] \[{{a}_{\min }}=g-\frac{2}{3}g=\frac{g}{3}\]
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