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VMMC VMMC Medical Solved Paper-2005

  • question_answer
    Air is expanded from 50 litre to 150 litre at 2 atmospheric pressure. The external work done is (1 atmosphere \[=1\times {{10}^{5}}\,N/{{m}^{2}}\]):

    A) \[2\times {{10}^{-8}}J\]

    B)                        \[2\times {{10}^{4}}\,J\]                              

    C) 200 J                     

    D)        2000 J

    Correct Answer: B

    Solution :

    From the formula, work done is \[W=P\times \Delta V=2\times {{10}^{5}}\times (150-50)\times {{10}^{-3}}\] \[=2\times {{10}^{4}}\,J\]


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