A) \[\frac{YA{{x}^{2}}}{2L}\]
B) \[\frac{YA{{x}^{2}}}{L}\]
C) \[Ya{{x}^{2}}L\]
D) \[\frac{Yax}{2L}\]
Correct Answer: A
Solution :
Energy stored is \[U=\frac{1}{2}\times force\times extesion=\frac{1}{2}Fx\] ?(i) and \[\Upsilon =\frac{F}{A}\frac{L}{x}\]or \[F=\frac{\Upsilon Ax}{L}\] ?(ii) From equations (i) and (ii), work done \[=\frac{1}{2}\left( \frac{\Upsilon Ax}{L} \right)\times x=\frac{1}{2}\frac{\Upsilon A{{x}^{2}}}{L}\]
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