A) more than one
B) less than one
C) equal to \[{{K}_{c}}\]
D) zero
Correct Answer: C
Solution :
\[{{H}_{2}}(g)+{{I}_{2}}(g)\rightleftharpoons 2HI(g)\] We know that, \[{{K}_{p}}={{K}_{c}}{{(RT)}^{\Delta {{n}_{g}}}}\] here, \[\Delta {{n}_{g}}=2-2=0\] \[\therefore \] \[{{K}_{p}}={{K}_{c}}{{(RT)}^{0}}={{K}_{c}}\]You need to login to perform this action.
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