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VMMC VMMC Medical Solved Paper-2005

  • question_answer
    A cyclic hydrocarbon molecule has all the carbon and hydrogen in a single plane. All the carbon-carbon bonds are of same length, less then \[\text{1}\text{.54}\overset{\text{o}}{\mathop{\text{A}}}\,,\] but more than \[\text{1}\text{.34}\overset{\text{o}}{\mathop{\text{A}}}\,.\] The C?bond angle will be:

    A)  \[{{109}^{o}}28\]            

    B)         \[{{100}^{o}}\]

    C)         \[{{180}^{o}}\]

    D)         \[{{120}^{o}}\]

    Correct Answer: D

    Solution :

    Cyclic hydrocarbon, with carbon-carbon bond length between \[1.34\overset{\text{o}}{\mathop{\text{A}}}\,\] and \[1.54\overset{\text{o}}{\mathop{\text{A}}}\,,\] is benzene in which due to resonance, C?C bond length is \[1.39\overset{\text{o}}{\mathop{\text{A}}}\,\] (i.e, between \[1.34\overset{\text{o}}{\mathop{\text{A}}}\,-1.54\overset{\text{o}}{\mathop{\text{A}}}\,\]). Benzene is a hexagonal molecule with bond-angle equal to \[\text{12}{{\text{0}}^{\text{o}}}.\]


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