A) \[C{{s}^{+}}\]
B) \[L{{i}^{+}}\]
C) \[N{{a}^{+}}\]
D) \[{{K}^{+}}\]
Correct Answer: A
Solution :
Atomic and ionic radii increase from top to bottom in a group due to the inclusion of another shell at every step. Hence \[\text{C}{{\text{s}}^{\text{+}}}\] ion will be the largest among given IA group ions \[\text{(N}{{\text{a}}^{+}}\text{,L}{{\text{i}}^{+}}\text{and }{{\text{K}}^{+}}\text{)}\]
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