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VMMC VMMC Medical Solved Paper-2005

  • question_answer
    For \[CaC{{O}_{3}}(s)\rightleftharpoons CaO(s)+C{{O}_{2}}(g)\]at \[927{{}^{o}}C,\Delta H =176\,kJmol;\] then \[\text{E}\] is:

    A) 180 kJ                  

    B) 186.4 kJ              

    C) 166.0 kJ        

    D) 160 kJ

    Correct Answer: C

    Solution :

    \[CaC{{O}_{3}}(g)\rightleftharpoons CaO(s)+C{{O}_{2}}(g)\] \[(\Delta {{n}_{g}}=1-0=1)\] We know that, \[\Delta H=\Delta E+\Delta {{n}_{g}}RT\] \[176=\Delta E +1\times 8.31\times {{10}^{-3}}\times (273\,+927)\]              \[\therefore \]  \[\Delta E=176-8.31\times {{10}^{-31}}\times 1200\]                                 \[=176-9.97\]  \[=166.03\,\text{kJ}\]


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