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VMMC VMMC Medical Solved Paper-2005

  • question_answer
    In a simple microscope, if the final image is located at 25 cm from the eye placed close to the lens, then the magnifying power is:

    A) \[\frac{25}{f}\]                 

    B)        \[1+\frac{25}{f}\]                            

    C) \[\frac{f}{25}\]                 

    D)        \[\frac{f}{25}+1\]

    Correct Answer: B

    Solution :

    Magnification of simple microscope \[m=1+\frac{D}{f}\] D = distance of final image So,          \[m=1+\frac{25}{f}\]


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