A) 10 J
B) 20 J
C) 30 J
D) 50 J
Correct Answer: A
Solution :
\[\beta =\frac{{{Q}_{2}}}{W}=\frac{{{T}_{L}}}{{{T}_{H}}-{{T}_{L}}}\] \[{{Q}_{2}}=\frac{273\times 1}{303\times 273}=\frac{273}{30}=9\,J\] Heat delivered to the surrounding \[{{Q}_{1}}={{Q}_{2}}+W=9+1=10\,J\]You need to login to perform this action.
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