A) \[-1.86{{\,}^{o}}C\]
B) \[1.86{{\,}^{o}}C\]
C) \[-3.92{{\,}^{o}}C\]
D) \[2.42{{\,}^{o}}C\]
Correct Answer: A
Solution :
Molality of cane sugar solution \[\frac{342}{342\times 1}=1\,m\] We know that, \[\Delta {{\Tau }_{f}}={{K}_{f}}.m=1.86\times 1={{1.86}^{o}}\] Hence, freezing point of solution \[=0.00-(1.86)=-1.86{{\,}^{o}}C\]You need to login to perform this action.
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